הצג להוכיח את הזהות להלן? 1 / cos290 + 1 / (sqrt3sin250) = 4 / sqrt3

הצג להוכיח את הזהות להלן? 1 / cos290 + 1 / (sqrt3sin250) = 4 / sqrt3
Anonim

# LHS = 1 / (cos290 ^ @) + 1 / (sqrt3sin250 ^ @) #

# 1 / (cos (360-70) ^ @) + 1 / (sqrt3sin (180 + 70) ^ @) #

# = 1 / (cos70 ^ @ @) - 1 / (sqrt3sin70 ^ @) #

# = (sqrt3sin70 ^ @ - cos70 ^ @) / (sqrt3sin70 ^ @ cos70 ^ @) #

# = 1 / sqrt3 (2 {sqrt3sin70 ^ @ - cos70 ^ @}) / (2sin70 ^ @ cos70 ^ @) #

# = 1 / sqrt3 (2 * 2 {sin70 ^ @ * (sqrt3 / 2) - cos70 ^ @ * (1/2)} / (sin140 ^ @) #

# = 1 / sqrt3 (4 {sin70 ^ @ * cos30 ^ @ - cos70 ^ @ * sin30 ^ @}) / (חטא (180-40) ^ @)

# (/ Sin40 ^ @) = 1 / sqrt3 (4 {חטא (sin30 ^ @ @)} /) = 4 / sqrt3 = RHS #

שים לב ש #cos (360-A) ^ @ = cosA and sin (180 + A) ^ @ = - sinA #

# 1 / cos290 + 1 / (sqrt3sin250) #

# = 1 / cos (270 + 20) + 1 / (sqrt3sin (270-20)) #

# = 1 / sin20 - 1 / (sqrt3cos20) #

# = sqrt3cos20-sin20 / (sqrt3sin20cos20) #

# = 2 / sqrt3 (sqrt3 / 2cos20-1 / 2sin20) / (sin20cos20) #

# = 4 / sqrt3 (sin60cos20-cos60sin20) / (2sin20cos20) #

# = 4 / sqrt3 חטא (60-20) / (2sin20cos20) #

# = 4 / sqrt3 sin40 / sin40 # #

# = 4 / sqrt3 #