# (a + b-x) / c + (+ c-x) / b + (c + b-x) / a + (4x) (+ b + c) = 1 #
(+ b + c) 3-1 = 0 (+ a bx) / c + 1 + (+ c +) + b + 1 + #
# + (+ b + c-x) / c + (+ c + b-x) / b + (c + b + a-x) / a-4 (1-x / (+ b + c) = 0 #
# (+ b + c-x) (1 + c + 1 / b + 1 / a) -4 (a + b + c-x) / a + b + c) = 0 #
# 1 (+ b + c-x) (1 + c + 1 / b + 1 / a-4 / a + b + c) = 0 #
לכן
# => (+ b + c-x) = 0 #
ל # (1 / c + 1 / b + 1 / a-4 / (a + b + c)) = 0 #
לפיכך # x = a + b + c #
